Adding Fractions

Add fractions with different denominators by finding a common denominator, then combining the numerators to get your answer.

ab+cd=ad+bcbd\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}

Solve a problem with Adding Fractions

Type the problem. The solver will use Adding Fractions where Adding Fractions is the right tool, and tell you when it is not.

Drag one in or paste from the clipboard. JPEG, PNG or WebP. You get the transcription to check before anything is solved.

How to get a better answer
  • Paste the whole problem, including the instruction word — "simplify", "solve for x" and "factor" lead to three different answers.
  • Say what you have already tried. "I got x = 4 and the book says 2" turns a solution into a diagnosis.
  • Set the level in the settings button. A calculus shortcut is not a better answer if you have not met derivatives yet.
  • For a photo, get the whole problem in frame and hold the page flat — you get the transcription to fix before anything is solved.

What each symbol means

What Adding Fractions takes
aa
bb
cc
dd
Adding Fractions
SymbolMeaning
aaThe numerator (top) of the first fraction; if confused with bb as the denominator, the fraction is inverted and the sum becomes wrong.
bbThe denominator (bottom) of the first fraction; cannot be zero, and swapping it with aa reverses the fraction's meaning.
ccThe numerator (top) of the second fraction; if treated as the denominator by mistake, the entire fraction flips and the answer is incorrect.
ddThe denominator (bottom) of the second fraction; cannot be zero, and confusing it with cc inverts the fraction and breaks the calculation.

When to use it

When you need to combine two fractions that have different denominators.

Level

Usually taught in: Pre-Algebra

Worked examples

1. Add two simple fractions with different denominators

Problem

Add 13+14\frac{1}{3} + \frac{1}{4}
  1. 13+14\frac{1}{3} + \frac{1}{4}

    We're adding two fractions with different denominators: 3 and 4.

  2. 1434+1343\frac{1 \cdot 4}{3 \cdot 4} + \frac{1 \cdot 3}{4 \cdot 3}

    We multiply the first fraction by 44\frac{4}{4} and the second by 33\frac{3}{3} to get denominators of 12.

  3. 412+312\frac{4}{12} + \frac{3}{12}

    After multiplying: 1×4=41 \times 4 = 4 in the first numerator and 1×3=31 \times 3 = 3 in the second.

  4. 4+312=712\frac{4 + 3}{12} = \frac{7}{12}

    With a common denominator, we add the numerators: 4+3=74 + 3 = 7.

Answer: 712\frac{7}{12}

When fractions have different denominators, we can't add the numerators directly. By converting both to have the same denominator using multiplication, we can combine them into one fraction.

2. Add fractions with negative values

Problem

Add 56+23\frac{5}{6} + \frac{-2}{3}
  1. 56+23\frac{5}{6} + \frac{-2}{3}

    We have a positive fraction and a negative fraction; we must keep track of the negative sign.

  2. 56+2232\frac{5}{6} + \frac{-2 \cdot 2}{3 \cdot 2}

    The LCD of 6 and 3 is 6 (since 3 divides evenly into 6), so we multiply the second fraction by 22\frac{2}{2}.

  3. 56+46\frac{5}{6} + \frac{-4}{6}

    After multiplying: 2×2=4-2 \times 2 = -4 in the numerator, keeping the negative sign.

  4. 5+(4)6=16\frac{5 + (-4)}{6} = \frac{1}{6}

    We add the numerators: 5+(4)=54=15 + (-4) = 5 - 4 = 1.

Answer: 16\frac{1}{6}

Negative fractions follow the same addition rules as positive ones. The key is to carefully track the negative signs through all steps.

3. Calculate total budget allocation for phone plan fees

Problem

Maya is comparing two phone plans. Plan A costs 38\frac{3}{8} of her monthly budget for the base fee and 16\frac{1}{6} for data charges. What fraction of her budget do these two charges use together?
  1. 38+16\frac{3}{8} + \frac{1}{6}

    We need to add the base fee (38\frac{3}{8} of budget) and data charges (16\frac{1}{6} of budget) to find the total.

  2. LCD of 8 and 6=24\text{LCD of } 8 \text{ and } 6 = 24

    We find the least common multiple of the denominators: 8=238 = 2^3 and 6=2×36 = 2 \times 3, so LCD is 24.

  3. 3383+1464=924+424\frac{3 \cdot 3}{8 \cdot 3} + \frac{1 \cdot 4}{6 \cdot 4} = \frac{9}{24} + \frac{4}{24}

    We multiply the first fraction by 33\frac{3}{3} and the second by 44\frac{4}{4}: 3×3=93 \times 3 = 9 and 1×4=41 \times 4 = 4.

  4. 9+424=1324\frac{9 + 4}{24} = \frac{13}{24}

    With a common denominator, we add the numerators: 9+4=139 + 4 = 13.

Answer: 1324\frac{13}{24}

Real-world problems often involve fractions that need to be added. The word 'together' signals that we should add. After translating the situation to a math problem, we apply fraction addition by finding a common denominator and adding the numerators.

Common mistakes

Where Adding Fractions usually goes wrong
Answer came out wrong
13+14=1+13+4=27\frac{1}{3} + \frac{1}{4} = \frac{1+1}{3+4} = \frac{2}{7}
Convert both fractions to use a common denominator: 13=412\frac{1}{3} = \frac{4}{12} and 14=312\frac{1}{4} = \frac{3}{12}, then add: 412+312=712\frac{4}{12} + \frac{3}{12} = \frac{7}{12}.
13+14=14+134=512\frac{1}{3} + \frac{1}{4} = \frac{1 \cdot 4 + 1}{3 \cdot 4} = \frac{5}{12}
Use the complete formula: ab+cd=ad+bcbd\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}, so 13+14=14+1334=712\frac{1}{3} + \frac{1}{4} = \frac{1 \cdot 4 + 1 \cdot 3}{3 \cdot 4} = \frac{7}{12}.
23+14=23+1434=1012\frac{2}{3} + \frac{1}{4} = \frac{2 \cdot 3 + 1 \cdot 4}{3 \cdot 4} = \frac{10}{12}
Pair correctly: the first numerator multiplies by the second denominator (adad), and the second numerator multiplies by the first denominator (bcbc), so 23+14=2×4+1×33×4=8+312=1112\frac{2}{3} + \frac{1}{4} = \frac{2 \times 4 + 1 \times 3}{3 \times 4} = \frac{8 + 3}{12} = \frac{11}{12}.
The mistakeWhy it is wrongThe fix
13+14=1+13+4=27\frac{1}{3} + \frac{1}{4} = \frac{1+1}{3+4} = \frac{2}{7}The denominator is not part of the numerator addition; you must find a common denominator first.Convert both fractions to use a common denominator: 13=412\frac{1}{3} = \frac{4}{12} and 14=312\frac{1}{4} = \frac{3}{12}, then add: 412+312=712\frac{4}{12} + \frac{3}{12} = \frac{7}{12}.
13+14=14+134=512\frac{1}{3} + \frac{1}{4} = \frac{1 \cdot 4 + 1}{3 \cdot 4} = \frac{5}{12}You must apply the full formula: the second numerator must also be multiplied by the first denominator (bcbc), not left out of the calculation.Use the complete formula: ab+cd=ad+bcbd\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}, so 13+14=14+1334=712\frac{1}{3} + \frac{1}{4} = \frac{1 \cdot 4 + 1 \cdot 3}{3 \cdot 4} = \frac{7}{12}.
23+14=23+1434=1012\frac{2}{3} + \frac{1}{4} = \frac{2 \cdot 3 + 1 \cdot 4}{3 \cdot 4} = \frac{10}{12}The formula requires each numerator to multiply by the opposite denominator; multiplying the first numerator by its own denominator gives the wrong result.Pair correctly: the first numerator multiplies by the second denominator (adad), and the second numerator multiplies by the first denominator (bcbc), so 23+14=2×4+1×33×4=8+312=1112\frac{2}{3} + \frac{1}{4} = \frac{2 \times 4 + 1 \times 3}{3 \times 4} = \frac{8 + 3}{12} = \frac{11}{12}.

Tips and when to use something else

  • Find the least common multiple (LCM) of the denominators to keep your numbers smaller—if you use the product of the denominators, you might need to simplify at the end.
  • If the fractions already have a common denominator, skip the formula and just add the numerators.
  • When one denominator divides evenly into the other (like 2 and 6), convert only the smaller fraction instead of both to keep numbers manageable.
  • If your final answer has a numerator and denominator with a common factor, use Simplifying Fractions to reduce it to lowest terms.

Frequently asked questions

Why can't I just add the numerators and denominators separately?
Because fractions don't work like whole numbers. A denominator tells you the size of the pieces you're working with. If you add the denominators, you're changing the size of the pieces, which gives you the wrong answer. The fractions must have the same denominator (same size pieces) before you can add them.
What's the difference between using the formula and just finding a common denominator?
They're the same process! The formula ad+bcbd\frac{ad + bc}{bd} always produces a result with a common denominator. In practice, you often use the least common multiple instead of the product bdbd, which keeps your numbers smaller.
What if one of the fractions has a negative denominator?
Negative denominators can create a negative fraction overall, but addition works the same way. It's better to rewrite a fraction like 34\frac{3}{-4} as 34\frac{-3}{4} first, so the negative sign is in the numerator, then follow the normal addition steps.
Do I always have to simplify my answer?
It's usually expected to simplify your final answer to lowest terms using the greatest common factor, but the unsimplified version is still mathematically correct. Check what your teacher or textbook requires.

Need a different method?

The full solver is not scoped to one formula — type any problem and it will pick the method.

Open the math solver

Reviewed 2026-09-18