Percent Error

Percent Error measures how far off a measurement is from the true value, as a percentage — use it to check accuracy of lab work or approximations.

%error=measuredactualactual×100%\%\,\text{error} = \left| \frac{\text{measured} - \text{actual}}{\text{actual}} \right| \times 100\%

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What each symbol means

SymbolMeaning

When to use it

Use Percent Error whenever you need to compare a measured or approximate value to the actual value and express the difference as a percentage.

Level

Usually taught in: Algebra I

Worked examples

1. Calculate percent error of a pen measurement

Problem

A student measures a pen and gets 14 cm, but the pen's actual length is 15 cm. What is the percent error?
  1. percent error=141515×100%\text{percent error} = \left| \frac{14 - 15}{15} \right| \times 100\%

    Substitute measured = 14 cm14 \text{ cm} and actual = 15 cm15 \text{ cm} into the formula.

  2. =115×100%= \left| \frac{-1}{15} \right| \times 100\%

    Simplify the numerator by subtracting: 1415=114 - 15 = -1.

  3. =115×100%= \frac{1}{15} \times 100\%

    Apply the absolute value: 1=1\left| -1 \right| = 1.

  4. =10015%=203%6.67%= \frac{100}{15}\% = \frac{20}{3}\% \approx 6.67\%

    Multiply and simplify: 10015=6.6\frac{100}{15} = 6.\overline{6}, approximately 6.67%6.67\%.

Answer: 6.6% (or approximately 6.67%)6.\overline{6}\% \text{ (or approximately } 6.67\%\text{)}

This example demonstrates the basic process: substitute values into the formula, simplify the subtraction, apply absolute value, and multiply by 100 to convert to a percentage. The small percent error (under 7%) indicates the measurement was fairly accurate, since the measured value was very close to the actual value.

2. Calculate percent error with decimal values

Problem

A chemist estimates the density of a liquid as 1.2 g/mL, but the actual density from a reference standard is 1.35 g/mL. What is the percent error in the chemist's estimate?
  1. percent error=1.21.351.35×100%\text{percent error} = \left| \frac{1.2 - 1.35}{1.35} \right| \times 100\%

    Substitute measured = 1.21.2 and actual = 1.351.35 into the formula.

  2. =0.151.35×100%= \left| \frac{-0.15}{1.35} \right| \times 100\%

    Simplify the numerator by subtracting: 1.21.35=0.151.2 - 1.35 = -0.15.

  3. =0.151.35×100%= \frac{0.15}{1.35} \times 100\%

    Apply the absolute value: 0.15=0.15\left| -0.15 \right| = 0.15.

  4. =15135×100%=19×100%= \frac{15}{135} \times 100\% = \frac{1}{9} \times 100\%

    Simplify the fraction: divide numerator and denominator by 15 to get 19\frac{1}{9}.

  5. =1009%11.11%= \frac{100}{9}\% \approx 11.11\%

    Divide: 100÷9=11.1100 \div 9 = 11.\overline{1}, approximately 11.11%11.11\%.

Answer: 11.1% (or approximately 11.11%)11.\overline{1}\% \text{ (or approximately } 11.11\%\text{)}

Working with decimals requires the same steps as integers, but demands careful arithmetic. The estimate of 1.21.2 was too low compared to the true value of 1.351.35, creating a percent error over 11%, which signals a moderately inaccurate estimate. Notice the absolute value correctly handles the negative difference.

3. Percent error in a coffee shop's sales counter

Problem

A coffee shop's digital sales counter recorded 52 cups of espresso sold one morning, but a manual recount revealed only 48 cups were actually sold. What is the percent error in the counter's recorded value?
  1. percent error=524848×100%\text{percent error} = \left| \frac{52 - 48}{48} \right| \times 100\%

    Substitute measured (counter reading) = 5252 and actual (manual count) = 4848 into the formula.

  2. =448×100%= \left| \frac{4}{48} \right| \times 100\%

    Simplify the numerator by subtracting: 5248=452 - 48 = 4 (the overcount).

  3. =448×100%= \frac{4}{48} \times 100\%

    Apply absolute value: 4=4\left| 4 \right| = 4 (already positive).

  4. =112×100%= \frac{1}{12} \times 100\%

    Simplify the fraction: 448=112\frac{4}{48} = \frac{1}{12} (divide both by 4).

  5. =10012%=253%8.33%= \frac{100}{12}\% = \frac{25}{3}\% \approx 8.33\%

    Divide: 100÷12=8.33100 \div 12 = 8.3\overline{3}, approximately 8.33%8.33\%.

Answer: 8.33% (or approximately 8.33%)8.3\overline{3}\% \text{ (or approximately } 8.33\%\text{)}

This real-world scenario shows why Percent Error matters: the counter reported 4 extra cups out of 48 actually sold, a percent error of about 8.3%. By calculating this error rate, the shop can decide whether the machine needs recalibration or if the error is within acceptable limits for daily operation.

Common mistakes

Where Percent Error usually goes wrong
Answer came out wrong
Dividing by the measured value instead of the actual value when calculating percent error.
Always divide by the actual (true or reference) value: the denominator must be actual, not measured.
Forgetting to use absolute value, so the percent error comes out negative when the measured value is less than the actual value.
Always apply absolute value to the numerator: use measuredactual\left| \text{measured} - \text{actual} \right| before dividing.
Computing the difference and multiplying by 100, but forgetting to divide by the actual value in between, yielding the raw change instead of the percent error.
Follow the complete formula in order: subtract to find the difference, divide by actual, then multiply by 100 — do not skip or reorder the division step.
The mistakeWhy it is wrongThe fix
Dividing by the measured value instead of the actual value when calculating percent error.This reverses the baseline for comparison; when the measured value exceeds the actual value, using measured as the divisor makes the error appear smaller than it should, and vice versa.Always divide by the actual (true or reference) value: the denominator must be actual, not measured.
Forgetting to use absolute value, so the percent error comes out negative when the measured value is less than the actual value.Percent Error measures the magnitude of inaccuracy, not its direction; a negative percent error is meaningless because error size is always positive or zero.Always apply absolute value to the numerator: use measuredactual\left| \text{measured} - \text{actual} \right| before dividing.
Computing the difference and multiplying by 100, but forgetting to divide by the actual value in between, yielding the raw change instead of the percent error.The raw difference depends on the scale of the measurement (a 1 cm error on a 5 cm object is very bad; a 1 cm error on a 1000 cm object is tiny), so it must be normalized by dividing by the actual value to make a fair comparison.Follow the complete formula in order: subtract to find the difference, divide by actual, then multiply by 100 — do not skip or reorder the division step.

Tips and when to use something else

  • Percent Error is always positive or zero (never negative) because absolute value ensures the result represents the size of the error, not its direction.
  • If your measured value exactly equals the actual value, percent error is exactly zero — this represents perfect measurement accuracy.
  • Do not confuse Percent Error with Percent Change; Percent Change compares an old value to a new value over time, while Percent Error compares a measured or estimated value to a known actual value.
  • In science and engineering, a percent error under 5% is usually considered excellent, 5–10% is acceptable, and over 10% typically signals the need for equipment calibration or method review.

Frequently asked questions

Why do we multiply by 100 at the end of the Percent Error formula?
Multiplying by 100 converts the decimal ratio into a percentage. The fraction erroractual\frac{\text{error}}{\text{actual}} produces a small decimal between 0 and 1, and multiplying by 100 scales it to a number between 0 and 100 (or higher if the error is large). This makes the result easier to interpret and compare.
Can Percent Error be greater than 100%?
Yes. If your measurement is off by more than the actual value itself, percent error exceeds 100%. For example, if the actual length is 5 cm5 \text{ cm} but you measure 12 cm12 \text{ cm}, the percent error is 1255×100%=140%\frac{|12 - 5|}{5} \times 100\% = 140\%. This signals a severely inaccurate measurement.
Do I have to include the percent sign (%) in my final answer?
Yes, always include the % sign in your answer. It tells the reader that your answer is a percentage, not a decimal or plain number—for example, 8.5%8.5\% and 0.0850.085 mean very different things. Always write the complete final answer with the % symbol.
What is the difference between Percent Error and Percent Change?
Percent Error compares a measured or estimated value to a known actual value and assesses measurement accuracy; use it in labs or when you have a reference standard. Percent Change compares an old value to a new value and measures how much something increased or decreased over time. Use Percent Change to track trends or growth rates.

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Reviewed 2026-09-18