Basic Probability

Basic Probability calculates the likelihood of an event by dividing favorable outcomes by the total number of possible outcomes.

P(A)=favourable outcomestotal outcomesP(A) = \frac{\text{favourable outcomes}}{\text{total outcomes}}

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What each symbol means

What Basic Probability takes
AA
PP
Basic Probability
SymbolMeaning
AAAn event is the specific outcome or group of outcomes you are interested in; if you confuse this with the probability itself, you may count the entire sample instead of just the favorable cases.
PPThe probability function outputs a number between 0 and 1 representing how likely an event is; if you treat the result as a count instead of a ratio, your answer will violate the definition of probability.

When to use it

Use Basic Probability to find the likelihood of a single event when all possible outcomes are equally likely.

Level

Usually taught in: Algebra I · Appears on: SAT, ACT

Worked examples

1. Find the probability of rolling a 2 on a die

Problem

A six-sided die is rolled. What is the probability of rolling a 2?
  1. P(A)=favourable outcomestotal outcomesP(A) = \frac{\text{favourable outcomes}}{\text{total outcomes}}

    We use the basic probability formula for this single event.

  2. Favorable outcomes=1\text{Favorable outcomes} = 1

    Only one face of the die shows a 2.

  3. Total outcomes=6\text{Total outcomes} = 6

    A standard die has six equally likely faces numbered 1 through 6.

  4. P(2)=16P(2) = \frac{1}{6}

    We substitute the counts into the formula.

Answer: P(2)=16P(2) = \frac{1}{6}

Since all faces of the die are equally likely, we use the basic probability formula directly. There is exactly one favorable outcome (rolling a 2) out of six total possible outcomes.

2. Find the probability of drawing a blue marble from a bag

Problem

A bag contains 4 red marbles, 3 blue marbles, and 2 green marbles. If you draw one marble at random, what is the probability of drawing a blue marble?
  1. P(A)=favourable outcomestotal outcomesP(A) = \frac{\text{favourable outcomes}}{\text{total outcomes}}

    We apply the basic probability formula to all equally likely outcomes.

  2. Favorable outcomes (blue)=3\text{Favorable outcomes (blue)} = 3

    The bag contains 3 blue marbles.

  3. Total outcomes (all marbles)=4+3+2=9\text{Total outcomes (all marbles)} = 4 + 3 + 2 = 9

    We add up all the marbles to find the total number of possible draws.

  4. P(blue)=39P(\text{blue}) = \frac{3}{9}

    We substitute the counts into the formula.

  5. 39=13\frac{3}{9} = \frac{1}{3}

    We simplify by dividing both numerator and denominator by their greatest common divisor, which is 3.

Answer: P(blue)=13P(\text{blue}) = \frac{1}{3}

Even though the bag holds different colors, each marble is equally likely to be drawn. We counted 3 favorable outcomes (blue marbles) out of 9 total equally likely outcomes and simplified to get P(blue)=1/30.333P(\text{blue}) = 1/3 \approx 0.333 or about 33%.

3. Find the probability of selecting an oatmeal cookie at a bake sale

Problem

At a school bake sale, there are 12 chocolate chip cookies, 8 oatmeal cookies, and 5 sugar cookies. If you pick one cookie at random, what is the probability of picking an oatmeal cookie?
  1. P(A)=favourable outcomestotal outcomesP(A) = \frac{\text{favourable outcomes}}{\text{total outcomes}}

    We apply the basic probability formula to this real-world scenario.

  2. Favorable outcomes (oatmeal)=8\text{Favorable outcomes (oatmeal)} = 8

    There are 8 oatmeal cookies available at the sale.

  3. Total outcomes (all cookies)=12+8+5=25\text{Total outcomes (all cookies)} = 12 + 8 + 5 = 25

    We add up all cookies to find the total number of equally likely choices.

  4. P(oatmeal)=825P(\text{oatmeal}) = \frac{8}{25}

    We substitute the counts into the formula; since 8 and 25 share no common factors, this fraction is already simplified.

Answer: P(oatmeal)=825P(\text{oatmeal}) = \frac{8}{25}

Each cookie is equally likely to be picked. The probability equals 8 favorable outcomes (oatmeal cookies) divided by 25 total outcomes (all cookies), so P(oatmeal)=8/25=0.32P(\text{oatmeal}) = 8/25 = 0.32 or 32%.

Common mistakes

Where Basic Probability usually goes wrong
Answer came out wrong
Writing P(A)=total outcomesfavorable outcomesP(A) = \frac{\text{total outcomes}}{\text{favorable outcomes}} (reversing numerator and denominator)
Always place favorable outcomes in the numerator and total outcomes in the denominator: P(A)=favorable outcomestotal outcomesP(A) = \frac{\text{favorable outcomes}}{\text{total outcomes}}.
Writing P=3P = 3 instead of P=39P = \frac{3}{9} when there are 3 favorable outcomes out of 9 total
Always express the final answer as a fraction or decimal: P=39=13P = \frac{3}{9} = \frac{1}{3} or P0.333P \approx 0.333, never as a raw count.
Assuming all outcomes are equally likely without checking; for example, using this formula for a weighted die or a shuffled versus unsorted deck
Always verify that all outcomes are equally likely before using this formula; if they are not, use Conditional Probability or Bayes' Theorem to account for the different likelihoods.
The mistakeWhy it is wrongThe fix
Writing P(A)=total outcomesfavorable outcomesP(A) = \frac{\text{total outcomes}}{\text{favorable outcomes}} (reversing numerator and denominator)This inverts the fraction and produces impossible results; when favorable outcomes are fewer than total outcomes, you get a number greater than 1, which violates the definition of probability.Always place favorable outcomes in the numerator and total outcomes in the denominator: P(A)=favorable outcomestotal outcomesP(A) = \frac{\text{favorable outcomes}}{\text{total outcomes}}.
Writing P=3P = 3 instead of P=39P = \frac{3}{9} when there are 3 favorable outcomes out of 9 totalProbability must always be a ratio expressed as a fraction or decimal between 0 and 1; a raw count like 3 is not a probability and loses the crucial information about total outcomes.Always express the final answer as a fraction or decimal: P=39=13P = \frac{3}{9} = \frac{1}{3} or P0.333P \approx 0.333, never as a raw count.
Assuming all outcomes are equally likely without checking; for example, using this formula for a weighted die or a shuffled versus unsorted deckThe basic probability formula only works when every outcome has an equal chance of occurring; if outcomes are not equally likely, the formula gives an incorrect answer.Always verify that all outcomes are equally likely before using this formula; if they are not, use Conditional Probability or Bayes' Theorem to account for the different likelihoods.

Tips and when to use something else

  • List all possible outcomes first, and verify that each one is equally likely before applying this formula.
  • If outcomes are not equally likely (such as a loaded die or biased coin), you cannot use this formula—reach for Conditional Probability or Bayes' Theorem instead.
  • Reduce fractions to simplest form when possible, but do not worry if a probability does not simplify; for example, 710\frac{7}{10} is a perfectly valid probability.
  • For scenarios involving multiple events, use the Multiplication Rule to find P(A and B)P(A \text{ and } B) or the Addition Rule to find P(A or B)P(A \text{ or } B).

Frequently asked questions

What is the difference between probability and odds?
Probability is the ratio of favorable outcomes to total outcomes, always giving a result between 0 and 1 (such as 12\frac{1}{2} or 0.5). Odds compare favorable to unfavorable outcomes (such as 1 to 1) and can be any positive number. Both contain the same information but express it differently.
Can a probability ever be greater than 1?
No, a probability is always between 0 and 1 inclusive, corresponding to 0% and 100%. If you calculate a probability greater than 1, you have made an error—most commonly by flipping the numerator and denominator or by miscounting your outcomes.
What should I do if the outcomes are not equally likely?
The basic probability formula assumes all outcomes are equally likely; if they are not (for example, a biased coin where heads appears 60% of the time), you cannot use this formula. Instead, use Conditional Probability or Bayes' Theorem to account for the different likelihoods of each outcome.
How do I figure out the total number of possible outcomes?
Use the Fundamental Counting Principle to count systematically. For a single die, count the number of faces; for drawing from a bag, count all items; for a sequence of events (such as rolling two dice), multiply the number of outcomes at each step.

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Reviewed 2026-09-18